$解:\overline{x}_甲=\frac {14.11+14.59+14.27+···+14.87}{16}=14.68(元)$
$极差:15.12-14.11=1.01(元)$
$s^2_甲=\frac 1{16}[(14.11-14.68)^2+(14.59-14.68)^2+···+(14.87-14.68)^2]=0.09(元^2)$
$\overline{x}_乙=\frac {15.49+15.53+15.51+···+16.17}{16}=16.16(元)$
$极差:16.8-15.49=1.31(元)$
$s^2_乙=\frac 1{16}[(15.49-16.16)^2+(15.53-16.16)^2+···+(16.17-16.16)^2]=0.16(元^2)$